Question

In a meter bridge experiment, the value of unknown resistance is 2$\Omega$. To get the balancing point at $40$ $\text{cm}$ distance from the same end, then what will be the resistance in the resistance box?

• A. $3\Omega$
• B. $6\Omega$
• C. $8\Omega$
• D. $9\Omega$

Answer 1

The correct option is A $3\Omega$


From above diagram, given data is
$S=2\Omega ;100-l=40\text{cm}$

Apply condition for balanced meter bridge,

$\frac{R}{l}=\frac{S}{100-l}$

$\frac{R}{60}=\frac{2}{40}$

$\therefore R=3\Omega$

Hence, option $\left(a\right)$ is correct.