In a metre-bridge experiment, when the resistances in the gaps are interchanged, the balance point did not shift at all. The ratio of resistances must be

very large

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very small

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equal to unity

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zero

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Solution

The correct option is C equal to unity
Before interchanging
$\frac{P}{Q} = \frac{l_{1}}{100 - l_{1}}$
After interchanging
$\frac{Q}{P} = \frac{l_{2}}{100 - l_{2}}$

Given $l_{1} = l_{2}$
$\Rightarrow \frac{P}{Q} = \frac{Q}{P}$
$\Rightarrow P^{2} = Q^{2}$
$\Rightarrow P = Q$
$\frac{P}{Q} = 1$

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In a metre-bridge experiment, when the resistances in the gaps are interchanged, the balance point did not shift at all. The ratio of resistances must be

The correct option is C equal to unityBefore interchangingPQ=l1100−l1After interchangingQP=l2100−l2Givenl1=l2⇒PQ=QP⇒P2=Q2⇒P=QPQ=1

The correct option is C equal to unity
Before interchanging
$\frac{P}{Q} = \frac{l_{1}}{100 - l_{1}}$
After interchanging
$\frac{Q}{P} = \frac{l_{2}}{100 - l_{2}}$

Given $l_{1} = l_{2}$
$\Rightarrow \frac{P}{Q} = \frac{Q}{P}$
$\Rightarrow P^{2} = Q^{2}$
$\Rightarrow P = Q$
$\frac{P}{Q} = 1$