In a mixture of milk and water, the proportion of water by weight is 75%. If, in the 60 gram mixture, 15 gram water was added, what would be the percentage of water in the new mixture?

83.33%

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75%

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86.67%

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80%

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Solution

The correct option is D 80%
Amount of water in 60 gram mixture $= \frac{75}{100} \times 60 = 45 g$
% of water after adding 15 g water $= \frac{45 + 15}{75} \times 100 = 80 %$

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In a mixture of milk and water, the proportion of water by weight is 75%. If, in the 60 gram mixture, 15 gram water was added, what would be the percentage of water in the new mixture?

The correct option is D 80%Amount of water in 60 gram mixture =75100×60=45g % of water after adding 15 g water =45+1575×100=80%

The correct option is D 80%
Amount of water in 60 gram mixture $= \frac{75}{100} \times 60 = 45 g$
% of water after adding 15 g water $= \frac{45 + 15}{75} \times 100 = 80 %$