In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

Open in App

Solution

Water in $60$ gm mixture $= 60 \times \frac{75}{100} = 45$ gm
and Milk $= 60 - 45 = 15$ gm.
After adding $15$ gm. of water in mixture, total water $= 45 + 15 = 60$ gm and weight of a mixture $= 60 + 15 = 75$ gm.So $%$ of water $= 100 \times \frac{60}{75} = 80 %$

Suggest Corrections

Similar questions

Q. In a mixture of milk and water, the proportion of water by weight was

75 %

. If in the 60 gm mixture, 15 gm water was added, what would be the percentage of water ? (Weight in gm)

Q. In a mixture of milk and water, the proportion of water by weight was 75 %. If in the 60 gm mixture, 15 gm water was added, what would be the percentage of water in the new mixture?

Q. In a mixture of milk and water, the proportion of water by weight is 75%. If, in the 60 gram mixture, 15 gram water was added, what would be the percentage of water in the new mixture?

Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure water. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm . What is the molecular weight of the solute?

0.98 g m

of the metal sulphate was dissolved in water and axcess of barium chloride was added. The precipitated barium sulphate weighted

0.95 g m

. Calculate the equivalent weight of the metal.

Join BYJU'S Learning Program

In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

Water in 60 gm mixture=60×75100=45 gm and Milk =60−45=15 gm.After adding 15 gm. of water in mixture, total water =45+15=60gm and weight of a mixture =60+15=75 gm.So % of water =100×6075=80%

Water in $60$ gm mixture $= 60 \times \frac{75}{100} = 45$ gm
and Milk $= 60 - 45 = 15$ gm.
After adding $15$ gm. of water in mixture, total water $= 45 + 15 = 60$ gm and weight of a mixture $= 60 + 15 = 75$ gm.So $%$ of water $= 100 \times \frac{60}{75} = 80 %$