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Question

In a month of twenty eight days, Rohan spends ₹x per day and saves ₹y per week for the first two weeks and he spends ₹2x per day and saves ₹0.5y per week in the last two weeks. What will be the algebraic expression that represents Rohan’s income this month?

A
42x + 3y
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B
6x + 3y
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C
42x + 21y
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D
21x + 1.5y
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Solution

The correct option is A 42x + 3y

Rohan spends ₹x per day and saves ₹y per week for the first two weeks.
So, as per the statement,
Total money that he spends in first two weeks
=14×Money spend per day=14x [2 weeks=14 day]

Total money he saves in first two weeks =2×Money save per week=2y

The algebraic expression for Rohan’s income in first two weeks would be,
14x+2y

Now,
He spends ₹2x per day and saves ₹0.5y per week in the last two weeks,
So, as per the statement,

Total money that he spends in last two weeks
=14×Money spend per day in last two weeks=14×2x=28x [2 weeks=14 day]

Total money he saves in last two weeks =2×Money save per week in last two weeks=2×0.5y=y

The algebraic expression for Rohan’s income in last two weeks would be,
28x+y

So, the total income of Rohan would be,
Money that he earns in first two weeks + Money that he earns in last two weeks
(14x+2y)+(28x+y)
Step 1:
Open brackets and group the like terms,
(14x+2y)+(28x+y)(14x+28x)+(2y+y)
Step 2:
Solve the brackets,
42x+3y

Hence, option (a) is correct.


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