In a multiple choice exam with 50 questions, 8 questions had A as the right answer, 13 had B, 15 had C and the rest had D. What is the probability that a question chosen at random had D as the correct answer?

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Solution

Probability that the answer was not D = $\frac{8 + 13 + 15}{50}$ = $\frac{36}{50}$ = 0.72
Probability that the answer was D = 1 – 0.72 = 0.28.

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In a multiple choice exam with 50 questions, 8 questions had A as the right answer, 13 had B, 15 had C and the rest had D. What is the probability that a question chosen at random had D as the correct answer?

Probability that the answer was not D = 8+13+1550 = 3650 = 0.72 Probability that the answer was D = 1 – 0.72 = 0.28.

Probability that the answer was not D = $\frac{8 + 13 + 15}{50}$ = $\frac{36}{50}$ = 0.72
Probability that the answer was D = 1 – 0.72 = 0.28.