In a musical chairs game, a person has been advised to stop playing the music at any time within $40$ seconds after its start. What is the probability that the music will stop within the first $15$ seconds?

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Solution

Total result $= 0$ sec to $40$ sec
Total possible outcomes $= 40$
So, $n (S) = 40$
Favourable results $= 0$ sec to $15$ sec
Favourable outcomes $= 15$
So, $n (E) = 15$
Hence, the probability that the music will stop in first $15$ sec $= n (E) / n (S) = 15 / 40 = 3 / 8$

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In a musical chairs game, a person has been advised to stop playing the music at any time within 40 seconds after its start. What is the probability that the music will stop within the first 15 seconds?

Total result =0 sec to 40 secTotal possible outcomes =40So, n(S)=40Favourable results =0 sec to 15 secFavourable outcomes =15So, n(E)=15Hence, the probability that the music will stop in first 15 sec =n(E)/n(S)=15/40=3/8

In a musical chairs game, a person has been advised to stop playing the music at any time within $40$ seconds after its start. What is the probability that the music will stop within the first $15$ seconds?

Total result $= 0$ sec to $40$ sec
Total possible outcomes $= 40$
So, $n (S) = 40$
Favourable results $= 0$ sec to $15$ sec
Favourable outcomes $= 15$
So, $n (E) = 15$
Hence, the probability that the music will stop in first $15$ sec $= n (E) / n (S) = 15 / 40 = 3 / 8$