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Modern Periodic Table

In a NaCI typ...

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In a NaCI type crystal distance between Na^+and Cl^-ion is 2.814 A^{†extdegree\overline{}} and the density of solid is 2.167 g cm^{-^3} then find out the value of Avogadroconstant.

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Q. In a NaCl type crystal distance between

N a^{+}

C l^{-}

2.814 ˚ A

and the density of solid is

2.167 g m / c m^{3}

then find out the value of Avogadro constant.

Q. Formula mass of NaCl is

58.45

^{- 1}

and density of its pure form is

2.167

^{- 3}

. The average distance between adjacent sodium and chloride ions in the crystal is

2.814 \times 10^{- 8}

cm. Calculate Avogadro's constant.

Q. Calculate the value of Avagadro's number if the density of

N a C l

2.165

^{- 3}

and distance between

N a^{+}

C l^{-}

N a C l

281

Q. The distance between

N a^{+}

C l^{-}

N a C l

3.165

c m^{- 3}

Q. What is the distance between

{N a}^{+}

{C l}^{-}

N a C l

crystal if its density is

2.165 g {c m}^{- 3}

.[Atomic mass of

N a - 23 u, C l = 35.5 u

, Avogadro,s Number=

6.023 \times 10^{23}

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