wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Neon discharge tube 2.9 × 1018 (Ne+) ions move to the right each second, while 1.2 × 1018 electrons move to the left per second; electron charge is 1.6 × 1019C. The current in the discharge tube is:

A
1A toward right
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.66A toward right
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.66A toward left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.66A toward right
Given, rate of flow of change, of
Ne+ ions, I1=2.9×1018×1.6×1019 [No. of ions × change of each ions]
=0.464A
of e, I2=1.2×1018×1.6×1019 [conventional current is taken opposite to flow of e]
=0.192A
Thus, net current
I=I1+I2
=0.464+0.192
I=0.656A towards right.

1048947_850855_ans_aeed379c26a54a51991ad537d62a66f7.png

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Charge_tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon