In a p-n junction, a potential barrier of 250 meV exists across the junction. A hole with a kinetic energy of 300 me V approaches the junction. Find the kinetic energy of the hole when it crosses the junction if the hole approached the junction (a) from the p-side and (b) from the n-side.

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Solution

Potential barrier 'd' = 250

Initial of hole = 330 meV

We know KE of the hole decreases when the junction is forward biased and increases when reverse biased in the given pn diode.

So,

(a) Final KE = $(300 - 250) m e V$

$= 50 m e V$

(b) Initial KE = $(300 + 250) m e V$

$= 550 m e V$

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In a p-n junction, a potential barrier of 250 meV exists across the junction. A hole with a kinetic energy of 300 me V approaches the junction. Find the kinetic energy of the hole when it crosses the junction if the hole approached the junction (a) from the p-side and (b) from the n-side.

Potential barrier 'd' = 250 Initial of hole = 330 meV We know KE of the hole decreases when the junction is forward biased and increases when reverse biased in the given pn diode. So, (a) Final KE = (300−250) me V =50 me V (b) Initial KE = (300+250) me V =550 me V

Potential barrier 'd' = 250

Initial of hole = 330 meV

We know KE of the hole decreases when the junction is forward biased and increases when reverse biased in the given pn diode.

So,

(a) Final KE = $(300 - 250) m e V$

$= 50 m e V$

(b) Initial KE = $(300 + 250) m e V$

$= 550 m e V$