In a $p - n$ junction, a potential barrier of $250 m e V$ exists across the junction. A hole with a kinetic energy of $3000 m e V$ approaches the junction. Find the kinetic energy of the hole when it crosses the junction if the hole approached the junction (a) from the $p -$ side and (b) from the $n -$ side.

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Solution

Potential barrier ‘d’ = 250 meV

Initial KE of hole = 300 meV

We know:
KE of the hole decreases when the junction is forward biased
and increases when reverse blased in the given ‘Pn’ diode.

So,

a) Final KE = (300 – 250) meV = 50 meV

b) Initial KE = (300 + 250) meV = 550 meV

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In a p−n junction, a potential barrier of 250 meV exists across the junction. A hole with a kinetic energy of 3000 meV approaches the junction. Find the kinetic energy of the hole when it crosses the junction if the hole approached the junction (a) from the p−side and (b) from the n−side.

Potential barrier ‘d’ = 250 meVInitial KE of hole = 300 meVWe know: KE of the hole decreases when the junction is forward biased and increases when reverse blased in the given ‘Pn’ diode.So,a) Final KE = (300 – 250) meV = 50 meVb) Initial KE = (300 + 250) meV = 550 meV

Potential barrier ‘d’ = 250 meV

Initial KE of hole = 300 meV

We know:
KE of the hole decreases when the junction is forward biased
and increases when reverse blased in the given ‘Pn’ diode.

So,

a) Final KE = (300 – 250) meV = 50 meV

b) Initial KE = (300 + 250) meV = 550 meV