In a $p - n$ junction, a potential barrier of $250 meV$ exists across the junction. A hole with a kinetic energy of $300 meV$ approaches the junction. Find the kinetic energy $(in meV)$ of the hole when it crosses the junction if the hole approached the junction from the $p -$ side.

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Solution

In a $p - n$ junction, the charge distribution and electric field is shown as
When a hole enters from $p -$ side, its kinetic energy decreases as the electric field opposes its motion.

If $U$ represents the barrier potential energy, by conservation of energy,

$K . E_{i} = U + K . E_{f}$

$K . E_{f} = (300 - 250) meV$

$\Rightarrow K . E_{f} = 50 meV$

Hence, $50$ is the correct answer.

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In a p−n junction, a potential barrier of 250 meV exists across the junction. A hole with a kinetic energy of 300 meV approaches the junction. Find the kinetic energy (in meV) of the hole when it crosses the junction if the hole approached the junction from the p−side.

In a $p - n$ junction, a potential barrier of $250 meV$ exists across the junction. A hole with a kinetic energy of $300 meV$ approaches the junction. Find the kinetic energy $(in meV)$ of the hole when it crosses the junction if the hole approached the junction from the $p -$ side.