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Question

In a p-n junction, the depletion region is 400 nm wide and an electric field of 5×105 V m1 exists in it. (a) Find the height of the potential barrier. (b) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side ?

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Solution

Depletion region 'd'

=400 nm=4×107 m

(a) Potential barrier 'V'

=E×d=5×d

(b) Kinetic Energy required

Potential barrier ×e=0.2 eV.

[Where 'e' = Orange of electron]


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