In a p-n-p transistor, working as a common base amplifier, current gain is 0.96 and emitter current is 7.2mA. The base current is

0.20 mA

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0.36 mA

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0.29 mA

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0.45 mA

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Solution

The correct option is C 0.29 mA
Current gain $= \frac{I_{C}}{I_{B}}$
$I_{C}$ = collector current
$I_{B}$ = base current
So, $I_{B} = \frac{I_{C}}{c u r r e n t g a i n} = \frac{7.2 m A}{0.96} = 7.5 m A$
As $I_{E} = I_{B} + I_{C}$
So, $I_{B} = I_{E} - I_{C}$
$= (7.5 - 7.2) m A = 0.3 m A$
$\approx 0.29 m A$

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In a PNP transistor working as a common-base amplifier, current gain is 0.96 and emitter current is 7.2 mA. The base current is

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