Question

In a p-type semiconductor, the acceptor level is situated $60meV$ above the valence band. The maximum wavelength of light required to produce a hole will be

• A. $0.207$ $\times$ $10$${}^{-5}$ $m$
• B. $2.07$ $\times$ $10$${}^{-5}$$m$
• C. $20.7$ $\times$ $10$${}^{-5}$$m$
• D. $2075$ $\times$$10$${}^{-5}$$m$

Answer 1

Answer: (B)

$2.07$ $\times$ $10$${}^{-5}$$m$

$\lambda =\frac{hc}{E}=\frac{6.62\times {10}^{-34}\times 3\times {10}^8}{(60\times {10}^{-3}\times 1.6\times {10}^{-19})}=2.07\times {10}^{-5}m$