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Question

In a pack of 52 playing cards, three cards are drawn at random with replacement. What is the probability of getting Jack in all 3 draws?

A
(452)2
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B
(113)3
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C
(313)3
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D
(352)3
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Solution

The correct option is B (113)3
Given,
Total cards in a pack =52
Number of jack =4

Probability of getting first Jack is P(A)=452=113

Probability of getting second Jack by replaceing the first is P(B)=452=113

Probability of getting third Jack by replaceing the second is P(B)=452=113

Now, we have to find probablity of getting Jack in all 3 draws with replacement.
P(A, B and C)=P(E)=P(A)×P(B)×P(C)

P(E)=113×113×113=(113)3

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