In a packet there are m different books, n different pens and p different pencils. The number of selections of at least one article of each type from the packet is
A
2m+n+p−1
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B
(m+1)(n+1)(p+1)−1
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C
2m+n+p
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D
(2m−1)(2n−1)(2p−1)
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Solution
The correct option is D(2m−1)(2n−1)(2p−1) Since each of (m+n+p) items has 2 choices of being selected or not selected; hence total no. of ways of selecting items =2×2×2×2×.................(m+n+p)times=2m+n+p but one case in this will be when none of the items is selected. Therefore, no. of ways of selecting at least one item of each type