In a parallel plate capacitor, the capacitance:

increases with increase in the distance between the plates

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decreases if a dielectric material is put between the plates

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increases with decrease in the distance between the plates

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increases with decrease in the area of the plates

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Solution

The correct option is C increases with decrease in the distance between the plates
capacitance is directly proportional to area(A) & dielectric constant(k) & inversely proportional to distance between the plates(d). $C = \frac{A ϵ_{0}}{d}$

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Similar questions

Statement 1 :

A parallel plate capacitor is charged by a battery of voltage

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Statement 2 :

The capacitance of a capacitor increases due to the introduction of a dielectric between the plates.

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In a parallel plate capacitor, the capacitance:

The correct option is C increases with decrease in the distance between the platescapacitance is directly proportional to area(A) & dielectric constant(k) & inversely proportional to distance between the plates(d). C=Aϵ0d

The correct option is C increases with decrease in the distance between the plates
capacitance is directly proportional to area(A) & dielectric constant(k) & inversely proportional to distance between the plates(d). $C = \frac{A ϵ_{0}}{d}$