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Capacitance of Parallel Plate Capacitor

In a parallel...

Question

In a parallel plate condenser if the distance between the plates is made half and the dielectric constant is doubled, then the capacity increases by a factor:

A

2 times

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B

4 times

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C

8 times

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D

16 times

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Solution

The correct option is A 4 times
We know,
$C = \frac{k l_{0} A}{d}$
Now distance is halved k id doubled
$C_{1} = \frac{(2 k) l_{0} A}{(^{d} / 2)}$
$C_{1} = 4 C$

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