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Question

In a parallelogram ABCD, a point K is taken on diagonal BD, when AK is extended it intersects CD and BC at M and L, respectively. If AK = 6 units, MK = 4 units, then LM equals

A
9
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B
6
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C
5
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D
24
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Solution

The correct option is C 5

The base of an isosceles triangle is half the length of each of its congruent sides.
Here the length AM=AK1+K1M
=6+4
=10 units.
We need to find length of LM which is the bases
i.e, LM=12AM
=12×10
=5 units.
Hence, the answer is 5.

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