In a parallelogram $A B C D$ , $A B = 10 c m$ and altitude corresponding to sides $A B$ and $A D$ are respectively, $7 c m$ and $8 c m$ , then find $A D$ .

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Solution

Area of parallelogram $= b \times h$
$A B \times D M = A D \times B N = b \times h$
$10 \times 7 = 8 \times A D$
$A D = \frac{70}{8} = \frac{35}{4}$
$= 8.75 c m$

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In a parallelogram ABCD, AB=10cm and altitude corresponding to sides AB and AD are respectively, 7cm and 8cm, then find AD.

Area of parallelogram =b×hAB×DM=AD×BN=b×h10×7=8×ADAD=708=354 =8.75cm

In a parallelogram $A B C D$ , $A B = 10 c m$ and altitude corresponding to sides $A B$ and $A D$ are respectively, $7 c m$ and $8 c m$ , then find $A D$ .

Area of parallelogram $= b \times h$
$A B \times D M = A D \times B N = b \times h$
$10 \times 7 = 8 \times A D$
$A D = \frac{70}{8} = \frac{35}{4}$
$= 8.75 c m$