In a parallelogram ABCD, AB > AD. Then

∠ A D B = ∠ D B C

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∠ C B D = ∠ D A B

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∠ A D B < ∠ B D C

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∠ A D B > ∠ B D C

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Solution

The correct option is D $∠ A D B > ∠ B D C$
$A B > A D$
$∴ ∠ A D B > ∠ A B D$ (angle opposite to longer side is greater)
$∴ ∠ A D B > ∠ B D C$ ( $∵ ∠ A B D = ∠ B D C$ as ABCD is a parallelogram)

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