Question

In a parallelogram $ABCD$, $AD=25cm$ and $AB=50cm$. If the altitude from a vertex $D$ on to $AB$ measures $22cm$, what is the altitude from a vertex $B$ on to $AD$?

Answer 1

Area of parallelogram is $A=bh$ where $b$ is the base and $h$ is the height of the parallelogram.

It is given that area of $ABCD$ is $50\times 22$ cm${}^2$

If the altitude from $B$ to $AD$ is $h$, and $ABCD=(25\times h)$ cm${}^2$

$25\times h=50\times 22$

$h=2\times 22=44$ cm

Hence, the altitude from a vertex $B$ on to $AD$ is $44$ cm.