Question

In a parallelogram $ABCD,\angle D={115}^o$, determine the measure of $\angle A$ and $\angle B$.

Answer 1

Given $\angle D={115}^{\circ }$

$\angle C=180-D$ $[\because$ interior angles of parallelogram are supplementary]

$=180-115$

$\angle C={65}^{\circ }$

As opposite sides are equal in parallelogram

$\angle B=\angle D={115}^{\circ }$

$\angle A=\angle C={65}^{\circ }$