In a parallelogram ABCD, angle D = 120 degree. Find the measurement of angle A.

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Solution

Dear Student

Given : ABCD is a parallelogram and angle D = $120^{0}$
Now
From the properties of parallelogram
angle A + angle D = $180^{0}$
$120^{0}$ + D = $180^{0}$
therefore D= $180^{0}$ - $120^{0}$ = $60^{0}$
Regards

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