In a parallelogram ABCD - - DAB -55- Find the angle - CBA-A- 125- 135-C- 140-D- 145-

The correct option is A 125^∘ Given, nbsp;∠ DAB=55^∘ Sum of consecutive angles of a parallelogram is equal to 180°. Hence, ∠ CBA+∠ DAB=180^∘ ∴∠ CBA=180^∘ 55^ ...

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Standard IX

Mathematics

Introduction to Quadrilaterals

In a parallel...

Question

In a parallelogram ABCD, $∠ D A B = 55^{\circ}$ . Find the angle $∠ C B A$ .

125^{\circ}

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135^{\circ}

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140^{\circ}

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145^{\circ}

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Solution

The correct option is A $125^{\circ}$

Given, $∠ D A B = 55^{\circ}$
Sum of consecutive angles of a parallelogram is equal to 180°.
Hence, $∠ C B A + ∠ D A B = 180^{\circ}$
$∴ ∠ C B A = 180^{\circ} - 55^{\circ}$
$= 125^{\circ}$

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In a parallelogram ABCD, ∠ DAB=55∘. Find the angle ∠ CBA.

The correct option is A 125∘ Given, ∠ DAB=55∘ Sum of consecutive angles of a parallelogram is equal to 180°. Hence, ∠ CBA+∠ DAB=180∘ ∴∠ CBA=180∘−55∘ =125∘

In a parallelogram ABCD, $∠ D A B = 55^{\circ}$ . Find the angle $∠ C B A$ .

The correct option is A $125^{\circ}$

Given, $∠ D A B = 55^{\circ}$
Sum of consecutive angles of a parallelogram is equal to 180°.
Hence, $∠ C B A + ∠ D A B = 180^{\circ}$
$∴ ∠ C B A = 180^{\circ} - 55^{\circ}$
$= 125^{\circ}$