In a parallelogram ABCD, determine the sum of angles $∠ B, ∠ C$ and $∠ D$ if $∠ A = 60^{\circ}$ [2 MARKS]

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Solution

According to the angle sum property of a quadrilateral,
$∠ A + ∠ B + ∠ C + ∠ D = 360^{\circ}$
$\Rightarrow 60^{\circ} + ∠ B + ∠ C + ∠ D = 360^{\circ}$
$\Rightarrow ∠ B + ∠ C + ∠ D = 360^{\circ} - 60^{\circ} = 300^{\circ}$

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