Question

In a parallelogram $ABCD$ diagonals $AC$ and $BD$ intersect at $O$ and $AC=6.8$ cm and $BD$ = 5.6 cm. Find the measures of $OC$ and $OD.$

Answer 1

Since the diagonals of a parallelogram bisect each other. Therefore, $O$ is the mid-point of $AC$ and $BD.$

Therefore,

$OC=\frac{1}{2}AC=\frac{1}{2}\times 6.8=3.4cm$

and, $OD=\frac{1}{2}BD=\frac{1}{2}\times 5.6=2.8cm$