Question

In a parallelogram $ABCD$ find the measure of all the angles if one angle measures ${68}^{\circ }.$

Answer 1

In parallelogram $ABCD,$ let the measure of $\angle A$ be ${68}^{\circ }.$

As, the sum of the adjacent angles in a parallelogram is equal to ${180}^{\circ }$. So,

$\angle A+\angle B={180}^{\circ }$

$\Rightarrow \angle B={180}^{\circ }-{68}^{\circ }$

$\Rightarrow \angle B={112}^{\circ }$

Also, opposite angles of a parallelogram are equal so,

$\angle B=\angle D={112}^{\circ }$

$\angle A=\angle C={68}^{\circ }$