In a parallelogram ABCD if angle A is 60- then the measure of angle B is-A- 120-B- 60-C- 90-D- 30-

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Construction of Standard Angles

In a parallel...

Question

In a parallelogram ABCD if angle A is 60^o then the measure of angle B is:

120^o

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60^o

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30^o

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90^o

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Solution

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A B C D

∠

A

60^{\circ}

In the adjoining figure, A, B, and C are three points on a circle O. If angle AOB = 90° and angle BOC = 120°, then angle ABC is:

∠ A = 60^{\circ}

∠ B : ∠ C : ∠ D = 2 : 4 : 6

∠ C .

\to A + \to B = \to C

| \to A | = 4, | \to B | = 5

| \to C | = \sqrt{61}

\to A

\to B

Measure of the four angles ∠A, ∠B, ∠C and ∠D in the given parallelogram will be

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