In a parallelogram ABCD, |−−→AB|=a,|−−→AD|=b and |−−→AC|=c. then which of the following is/are CORRECT?
In the adjoining figure, if BC=a,AC=b,AB=c and ∠CAB=120∘, then which of the following is the correct relation?
In the adjoining figure, if BC = a, AC = b, AB = c and ∠CAB=120∘, then the correct relation is-
In the adjoining figure, if BC=a, AC=b, AB=c and ∠CAB=120∘, then the correct relation is
If a + b + c = 2s, then prove the following identities
(a) s2 + (s − a)2 + (s − b)2 + (s − c)2 = a2 + b2 + c2
(b) a2 + b2 − c2 + 2ab = 4s (s − c)
(c) c2 + a2 − b2 + 2ca = 4s (s − b)
(d) a2 − b2 − c2 + 2ab = 4(s − b) (s − c)
(e) (2bc + a2 − b2 − c2) (2bc − a2 + b2 + c2) = 16s (s − a) (s − b) (s − c)
(f)