In a parallelogram ABCD, P is a point in interior of parallelogram ABCD. If ar (||gm ABCD) = 18 cm² then [ar ∆APD) + ar(∆CPB)] is :

15 cm²

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12 cm²

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18 cm²

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9 cm²

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Solution

The correct option is D
9 cm²

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In a ||gm ABCD,if P and Q are midpoints if AB and CD respectively and ar(||gm ABCD)= $16 c m^{2}$ then ar(||gm~APQD)=?

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(b) $12 c m^{2}$

(d) $9 c m^{2}$

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