In a parallelogram, if a diagonal bisects the angles through which it passes, then the parallelogram is a
Rhombus
(i) ABCD is a parallelogram (given)
(ii) Let ∠ADC=∠ABC=2x∘ (Opposite angles of a parallelogram)
(iii) DB bisects ∠ADC and ∠ABC (given)
(iv) ∴ ∠ADB=∠BDC=∠CBD=∠DBA=x∘
(v) ΔADB is Isosceles (base angles are equal)
(vi) ∴ AD=AB (vii) ABCD is a rhombus (all sides are equal)