In a parallelogram it is being given that base = 14 dm and height = 6.5 dm. Find its area in $m^{2}$ .

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Solution

Area = $b a s e \times h e i g h t$
Area= $14 d m \times 6.5 d m$
Area= $91 d m^{2}$
Area= $9100 c m^{2}$
Area= $0.91 m^{2}$

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In a parallelogram it is being given that base = 14 dm and height = 6.5 dm. Find its area in m2.

Area =base×heightArea=14dm×6.5dmArea=91dm2Area=9100cm2Area=0.91m2

In a parallelogram it is being given that base = 14 dm and height = 6.5 dm. Find its area in $m^{2}$ .

Area = $b a s e \times h e i g h t$
Area= $14 d m \times 6.5 d m$
Area= $91 d m^{2}$
Area= $9100 c m^{2}$
Area= $0.91 m^{2}$