In a parallelogram PQRS- if - - 25- find the value of -A- 115-B- 155-C- 100-D- 200-

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Angle Sum Property of Triangle

In a parallel...

Question

In a parallelogram PQRS, if ∠𝑄𝑅𝑇 = 25°, find the value of ∠𝑃𝑆𝑅.

A. 115°
B. 155°
C. 100°
D. 200°

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Solution

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Δ A B C \sim Δ P Q R

A (Δ A B C) = 144 c m^{2}

A (Δ P Q R) = 100 c m^{2}

tan 25^{o} = a,

\frac{tan 155^{o} - tan 115^{o}}{1 + tan 155^{o} . tan 115^{o}} = \frac{1 - a^{2}}{2 a}

[2 M a r k s]

(i n c m^{2})

P Q R S

P R = 24 c m

Q U = S T = 8 c m

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