In a parallelogram PQRS , OS $= 5$ cm and PR is $6$ cm more than QS. Find OP.

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Solution

Given
$O S = 5 x c m$

$Q S = 2 (O S)$

$Q S = 10 x c m$

$P R = Q S + 6 = 16 x c m$

$O P = \frac{1}{2} (P R) = \frac{1}{2} (16) = 8 x c m$

$O P = 8 x c m$

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