Question

In a parallelogram $PQRS$, $PQ=4.5$ $cm$, $PR=6$ $cm$, $QS=7.8$ $cm$ and the diagonals $PR$ and $QS$ intersect each other at $O$, then to draw a parallelogram we have to first draw:

• A. $\Delta PQR$
• B. $\Delta ROS$
• C. $\Delta QOR$
• D. $\Delta PRS$

Answer 1

The correct option is B $\Delta ROS$

The intersection point of the diagonals of the parallelogram is already given.
Point of intersection 'O' divides the parallelogram into $4$ triangles.

Length of diagonals is given, so we get a triangle in which two sides are half of the diagonals and third side is $PQ=4.5$ cm which is given

$\Delta POQ$ and $\Delta SOR$ are congruent. Since, diagonals bisects each other.

Similarly, $\Delta POS$ and $\Delta QOR$ are also congruent.
So, to complete the parallelogram, we first draw the triangle $SOR$.
Hence, option B is correct.