In a particular family, each boy has as many brothers as the sisters, but each girl has twice as many brothers as that of sisters. How many boys and girls are there in the family?
4, 3
Let No. of boys be X and girls be Y
Each boy has as many brothers as sisters
Hence, (X - 1) = Y
Rearranging we get,
X - Y = 1 ……….(1)
Now, each girl has twice as many brothers as that of sisters
Hence, 2 * (Y - 1) = X
Solving the bracket we get, 2Y - 2 = X
Rearranging we get,
-X + 2Y = 2 ……….(2)
Adding (1) and (2), we get
Y = 3 i.e. No. of girls
Substituting value of Y in equation (1),
X - 3 = 1
Solving this we get,
X = 4 i.e. No. of boys
Therefore, there are 4 boys and 3 girls in the family.