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Standard X

Biology

The Punnett Tool

In a pea plan...

Question

In a pea plant, flower colour purple is dominant over white and fruit shape round is dominant over wrinkled. Crossing was performed between two pure lines-one having purple flower and round fruit, and another with white flower and wrinkled fruit. Plants of F1 were allowed to self-fertilize, and about 960 plants survived in F2. If the traits follow Mendelian inheritance, the number of plants in F2 that would have yellow flowers and round fruits in F2 are:

960

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540

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180

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Solution

The correct option is B
540

We know that the phenotypic ratio in a dihybrid cross is 9:3:3:1

Where 9/16 is the share of offsprings having both dominant character ( as per question it is plant with yellow flower and round fruit).
Total number of f2 plant having yellow flower and round fruit= 9/16× 960 = 540

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