Question

in a pentagon ABCDE, AE and BC are equal and parallel and the three sides AB,CD and DE are equal to one another. If angle A is 102 degrees . Find angles AEC and BCD.

Answer 1

$$\begin{gathered} Dearstudent, \\ AE\parallel BCandABistransversal \\ therefore\angle BAE+\angle ABC=180° \\ \Rightarrow 102°+\angle ABC=180° \\ \Rightarrow \angle ABC=78° \\ NowonjoiningECwegetABCEaparalle\log ram \\ therefore\angle AEC=\angle ABC=78° \\ Regards \end{gathered}$$