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Standard VIII
Mathematics
Mode
In a perfectl...
Question
In a perfectly symmetrical distribution, the mode and the mean are 42 and 49 respectively. Find the approximate median of this distribution.
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Solution
mode=
(3×median)-(2×mean)
here,
Mode=42
Mean =49
So, substitute in equation.
42= 3× median -2×49
42 =3 median -98
Or,
42+98 = 3×median
140 = 3× median
Ir,
Median =140/3 =46.66
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