CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a photo cell 4 unit photo electric current is flowing . The distance between sourece and cathode is 4 distance between source and cathode becomes 1 unit . What will be photo electric current now?

Open in App
Solution

On doubling intensity becomes one fourth i.e. only one fourth of electrons strike the target in comparison to previous number since photoelectric effect is one photon-one photon phenomena so only one fourth of photo electrons are emitted out of the target hence reducing the current to one fourth the previous value

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Photon Theory
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon