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Question

In a photo cell 4 unit photo electric current is flowing . The distance between sourece and cathode is 4 distance between source and cathode becomes 1 unit . What will be photo electric current now?

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Solution

On doubling intensity becomes one fourth i.e. only one fourth of electrons strike the target in comparison to previous number since photoelectric effect is one photon-one photon phenomena so only one fourth of photo electrons are emitted out of the target hence reducing the current to one fourth the previous value

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