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In a photoele...

Question

In a photoelectric cell, illuminated with a certain radiation, the minimum negative anode of potential with respect to emitting metal required to stop the electron is $2 V .$ the minimum KE of the photoelectrons is

A

0 e V

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B

1 e V

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C

2 e V

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D

4 e V

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Solution

The correct option is B $2 e V$
Given,
$V_{0} = 2 V$
The minimum kinetic energy of the photo electron is
$K_{m i n} = e V_{0}$
$K_{m i n} = 2 e V$
The correct option is C.

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