In a photoelectric effect experiment, for radiation with frequency υ0 with hυ0=8eV, electrons are emitted with energy 2 eV. What is the energy of the electrons emitted for incoming radiation of frequency 1.25υ0 ?
A
1 eV
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B
3.25 eV
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C
4eV
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D
9.25eV
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Solution
The correct option is B 4eV Photoelectric Effect KEmax=hvo−Wo 2ev=8eV−Wo Wo=6eV Now for frequency 1.25vo KEmax=1.25hvo−Wo KEmax=1.25(8)−6eV=4eV