In a photoelectric effect experiment, if 'f' is the frequency of incident radiation on the metal surface and 'I' is the intensity of the incident radiation, then

If 'f' is increased keeping 'I' and work function constant, saturation current increases.

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If 'I' is increased keeping 'f' and work function contant saturation current increases.

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If work function is decreased keeping 'f' and 'I' constant, then stopping potential increases but saturation current remains same.

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On increasing distance between cathod and anode, stopping potential remains same.

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Solution

The correct options are
B If 'I' is increased keeping 'f' and work function contant saturation current increases.
C If work function is decreased keeping 'f' and 'I' constant, then stopping potential increases but saturation current remains same.
D On increasing distance between cathod and anode, stopping potential remains same.
Option A) If intensity is same and the frequency is increased, then the photon flux doesn't change, only maximum K.E of ejected electrons increases.
Option B) If intensity is increased while keeping 'f' constant, the photon flux increases. So, the current increases.
Option C) If work function is decreased while everything is same, the KE of the photo electrons increases but the number of photo electrons remains the same.
Option D) Stopping potential only depends on the K.E of the electron.

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Similar questions

$\begin{matrix} C o l u m n I & C o l u m n I I (A) If v (frequency) is increased keeping I (intensity) and Φ (work function) constant & (P) Stoping potential increases (B) If I is increased keeping v and Φ constant & (Q) Saturation photocurrent increases (C) If the distance between anode and cathode increases. & (R) Maximum KE of the photoelectrons increase (D) If Φ is decreased keeping v and I constant & (S) Stopping potential remains the same \end{matrix}$

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