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Question

In a photoelectric emission, electrons are ejected from metals P and Q by light of frequency f. The potential difference V required to stop the electrons is measured for various frequencies. If Q has a greater work function, then P which graph illustrates the expected results?

A
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B
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C
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D
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Solution

The correct option is D
Electrons gets ejected, if ,hνth>ϕνth>ϕh

Where, νth=Threshold frequencyϕ=Work function

The graph between Vvsf has a constant slope of (he), so both lines must be parallel.

But the work function Q is greater than P [i.e., Threshold frequency of Q is greater than P]

ϕQ>ϕP (νth)Q>(νth)P

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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