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The Photon Model

In a photoele...

Question

In a photoelectric emission process, the maximum energy of the photoelectrons increases with increasing intensity of the incident light.
(IIT-JEE, 1986)

A

True

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B

False

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Solution

The correct option is B False
$(K . E)_{m a x} = h v - h v_{0} \Rightarrow (K E)_{m a x} α v$
Thus, maximum kinetic energy is proportional to frequency and not intensity.

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Q. Assertion :The kinetic energy of the photoelectron ejected increases with increase in intensity of incident light. Reason: Increase in intensity of incident light increases the rate of emission.

Q. (A) The kinetic energy of the photoelectron ejected increases with increase in the intensity of incident radiation.
(R) Increase in intensity of incident light increases the rate of emission.

State True or False.

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Q. Statement- 1: The kinetic energy of photoelectrons increases with increase in frequency of incident light.

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Q. Assertion :Kinetic energy of photoelectrons increases with increase in the frequency of incident radiation. Reason: The number of photoelectrons ejected increases with increase in intensity of incident radiation.

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