In a photoelectric experiment, a white light is incident on the the metal surface. It is of a particular frequency causes emission of the electron from the surface of the metal. Which of the following actions would produce more electrons per second?

Increase the frequency of the light

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Decrease the frequency of the light

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Increase the intensity (brightness) of the light

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Decrease the intensity (brightness) of the light

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Increase the wavelength of the light

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Solution

The correct option is D Increase the intensity (brightness) of the light
The photoelectric current, that is, electrons produced per second depends directly upon the intensity of incident light.
However the kinetic energy of the ejected electrons depend only upon the frequency of incident light.

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In a photoelectric experiment, a white light is incident on the the metal surface. It is of a particular frequency causes emission of the electron from the surface of the metal. Which of the following actions would produce more electrons per second?

The correct option is D Increase the intensity (brightness) of the lightThe photoelectric current, that is, electrons produced per second depends directly upon the intensity of incident light.However the kinetic energy of the ejected electrons depend only upon the frequency of incident light.

The correct option is D Increase the intensity (brightness) of the light
The photoelectric current, that is, electrons produced per second depends directly upon the intensity of incident light.
However the kinetic energy of the ejected electrons depend only upon the frequency of incident light.