In a photoelectric experiment for 4000 Å incident radiation, the potential difference to stop the ejection is 2 V. If the incident light is changed to 3000 Å, then the potential required to stop the ejection of electrons will be
A
2 V
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B
Less than 2 V
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C
Zero
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D
Greater than 2 V
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Solution
The correct option is D Greater than 2 V According to Einstein's photoelectric equation E=W0+Kmax⇒V0=hce[1λ−1λ0] Hence if λ decreases V0 increases.