In a photoelectric experiment, if both the intensity and frequency of the incident light are doubled, then the saturation photoelectric current.
A
remains constant
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B
is halved
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C
is doubled
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D
becomes four times
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Solution
The correct option is B is doubled The saturation photoelectric current is directly proportional to the
intensity of incident radiation but it is independent of its frequency.
Therefore the saturation photoelectric current becomes doubled, when
both intensity and frequency of the incident light are doubled.